Base | Representation |
---|---|
bin | 1100001100101001011010… |
… | …0001010011010010010111 |
3 | 1202111010012110001001102112 |
4 | 3003022112201103102113 |
5 | 3224213033240212023 |
6 | 44305041305301235 |
7 | 2552641215240035 |
oct | 303122641232227 |
9 | 52433173031375 |
10 | 13411413210263 |
11 | 4300826138972 |
12 | 160727b19481b |
13 | 7638c9a094c3 |
14 | 345189cdb555 |
15 | 183cdd042478 |
hex | c3296853497 |
13411413210263 has 2 divisors, whose sum is σ = 13411413210264. Its totient is φ = 13411413210262.
The previous prime is 13411413210131. The next prime is 13411413210289. The reversal of 13411413210263 is 36201231411431.
It is a strong prime.
It is an emirp because it is prime and its reverse (36201231411431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13411413210263 - 230 = 13410339468439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411413290263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705706605131 + 6705706605132.
It is an arithmetic number, because the mean of its divisors is an integer number (6705706605132).
Almost surely, 213411413210263 is an apocalyptic number.
13411413210263 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411413210263 is an equidigital number, since it uses as much as digits as its factorization.
13411413210263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 32.
Adding to 13411413210263 its reverse (36201231411431), we get a palindrome (49612644621694).
The spelling of 13411413210263 in words is "thirteen trillion, four hundred eleven billion, four hundred thirteen million, two hundred ten thousand, two hundred sixty-three".
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