13411414133400 has 192 divisors, whose sum is σ = 42209467171200. Its totient is φ = 3521866613760.

The previous prime is 13411414133399. The next prime is 13411414133417. The reversal of 13411414133400 is 433141411431.

It is a super-3 number, since 3×13411414133400³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 128949819 + ... + 129053781.

It is an arithmetic number, because the mean of its divisors is an integer number (219840974850).

Almost surely, 2^{13411414133400} is an apocalyptic number.

13411414133400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13411414133400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21104733585600).

13411414133400 is an abundant number, since it is smaller than the sum of its proper divisors (28798053037800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13411414133400 is a wasteful number, since it uses less digits than its factorization.

13411414133400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107258 (or 107249 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 13411414133400 its reverse (433141411431), we get a palindrome (13844555544831).

The spelling of 13411414133400 in words is "thirteen trillion, four hundred eleven billion, four hundred fourteen million, one hundred thirty-three thousand, four hundred".