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134114343311 = 1310316487947
BaseRepresentation
bin111110011100111010…
…1100111100110001111
3110211011122210112121102
41330321311213212033
54144131232441221
6141340011453315
712455323052234
oct1747165474617
9424148715542
10134114343311
1151972061163
1221baa75723b
13c8543bc4c0
1466c3aa578b
15374e17330b
hex1f39d6798f

134114343311 has 4 divisors (see below), whose sum is σ = 144430831272. Its totient is φ = 123797855352.

The previous prime is 134114343299. The next prime is 134114343329. The reversal of 134114343311 is 113343411431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134114343311 - 234 = 116934474127 is a prime.

It is a super-4 number, since 4×1341143433114 (a number of 46 digits) contains 4444 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134114343911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5158243961 + ... + 5158243986.

It is an arithmetic number, because the mean of its divisors is an integer number (36107707818).

Almost surely, 2134114343311 is an apocalyptic number.

134114343311 is a deficient number, since it is larger than the sum of its proper divisors (10316487961).

134114343311 is a wasteful number, since it uses less digits than its factorization.

134114343311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10316487960.

The product of its digits is 5184, while the sum is 29.

Adding to 134114343311 its reverse (113343411431), we get a palindrome (247457754742).

The spelling of 134114343311 in words is "one hundred thirty-four billion, one hundred fourteen million, three hundred forty-three thousand, three hundred eleven".

Divisors: 1 13 10316487947 134114343311