13411611131 has 2 divisors, whose sum is σ = 13411611132. Its totient is φ = 13411611130.

The previous prime is 13411611089. The next prime is 13411611133. The reversal of 13411611131 is 13111611431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13411611131 is a prime.

It is a super-2 number, since 2×13411611131² (a number of 21 digits) contains 22 as substring.

Together with 13411611133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13411611097 and 13411611106.

It is not a weakly prime, because it can be changed into another prime (13411611133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705805565 + 6705805566.

It is an arithmetic number, because the mean of its divisors is an integer number (6705805566).

Almost surely, 2^13411611131 is an apocalyptic number.

13411611131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411611131 is an equidigital number, since it uses as much as digits as its factorization.

13411611131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 216, while the sum is 23.

The spelling of 13411611131 in words is "thirteen billion, four hundred eleven million, six hundred eleven thousand, one hundred thirty-one".