Base | Representation |
---|---|
bin | 111110011101000101… |
… | …1100110000111110000 |
3 | 110211012001122020101021 |
4 | 1330322023212013300 |
5 | 4144134221320212 |
6 | 141340335145224 |
7 | 12455423035426 |
oct | 1747213460760 |
9 | 424161566337 |
10 | 134120104432 |
11 | 51975336616 |
12 | 21bb0675214 |
13 | c855658852 |
14 | 66c4765116 |
15 | 374e910307 |
hex | 1f3a2e61f0 |
134120104432 has 10 divisors (see below), whose sum is σ = 259857702368. Its totient is φ = 67060052208.
The previous prime is 134120104429. The next prime is 134120104441. The reversal of 134120104432 is 234401021431.
It is a junction number, because it is equal to n+sod(n) for n = 134120104397 and 134120104406.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4191253248 + ... + 4191253279.
Almost surely, 2134120104432 is an apocalyptic number.
It is an amenable number.
134120104432 is a deficient number, since it is larger than the sum of its proper divisors (125737597936).
134120104432 is an equidigital number, since it uses as much as digits as its factorization.
134120104432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8382506535 (or 8382506529 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134120104432 its reverse (234401021431), we get a palindrome (368521125863).
The spelling of 134120104432 in words is "one hundred thirty-four billion, one hundred twenty million, one hundred four thousand, four hundred thirty-two".
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