Base | Representation |
---|---|
bin | 111110011101001101… |
… | …0100011000111101111 |
3 | 110211012100000101102200 |
4 | 1330322122203013233 |
5 | 4144141222234203 |
6 | 141340555152543 |
7 | 12455501252553 |
oct | 1747232430757 |
9 | 424170011380 |
10 | 134124024303 |
11 | 51977573685 |
12 | 21bb1a45753 |
13 | c8563cbab9 |
14 | 66c50a5863 |
15 | 374ee369a3 |
hex | 1f3a6a31ef |
134124024303 has 24 divisors (see below), whose sum is σ = 196676478336. Its totient is φ = 88058955600.
The previous prime is 134124024289. The next prime is 134124024323. The reversal of 134124024303 is 303420421431.
134124024303 is a `hidden beast` number, since 1 + 3 + 412 + 4 + 0 + 243 + 0 + 3 = 666.
It is not a de Polignac number, because 134124024303 - 25 = 134124024271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134124024323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2525008 + ... + 2577578.
It is an arithmetic number, because the mean of its divisors is an integer number (8194853264).
Almost surely, 2134124024303 is an apocalyptic number.
134124024303 is a deficient number, since it is larger than the sum of its proper divisors (62552454033).
134124024303 is a wasteful number, since it uses less digits than its factorization.
134124024303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56875 (or 56872 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 134124024303 its reverse (303420421431), we get a palindrome (437544445734).
The spelling of 134124024303 in words is "one hundred thirty-four billion, one hundred twenty-four million, twenty-four thousand, three hundred three".
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