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13413005511350 = 2522595771033451
BaseRepresentation
bin1100001100101111010101…
…1011011100101010110110
31202111021022102020022212212
43003023311123130222312
53224224313402330400
644305503310013422
72553025531463204
oct303136533345266
952437272208785
1013413005511350
114301472a31285
1216076444a7272
13763ac1877bb3
1434529b58a074
15183d82c20335
hexc32f56dcab6

13413005511350 has 24 divisors (see below), whose sum is σ = 24948310502808. Its totient is φ = 5365176344000.

The previous prime is 13413005511313. The next prime is 13413005511359. The reversal of 13413005511350 is 5311550031431.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13413005511359) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12462125 + ... + 13495575.

It is an arithmetic number, because the mean of its divisors is an integer number (1039512937617).

Almost surely, 213413005511350 is an apocalyptic number.

13413005511350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13413005511350 is a deficient number, since it is larger than the sum of its proper divisors (11535304991458).

13413005511350 is a wasteful number, since it uses less digits than its factorization.

13413005511350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1293040 (or 1293035 counting only the distinct ones).

The product of its (nonzero) digits is 13500, while the sum is 32.

Adding to 13413005511350 its reverse (5311550031431), we get a palindrome (18724555542781).

The spelling of 13413005511350 in words is "thirteen trillion, four hundred thirteen billion, five million, five hundred eleven thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 259577 519154 1033451 1297885 2066902 2595770 5167255 6489425 10334510 12978850 25836275 51672550 268260110227 536520220454 1341300551135 2682601102270 6706502755675 13413005511350