Base | Representation |
---|---|
bin | 11000111110111110… |
… | …00111101010010111 |
3 | 1021121210012210102102 |
4 | 30133133013222113 |
5 | 204432231402211 |
6 | 10054550232315 |
7 | 653250631406 |
oct | 143737075227 |
9 | 37553183372 |
10 | 13413153431 |
11 | 5763414777 |
12 | 272405569b |
13 | 1359b6a2a2 |
14 | 91359563d |
15 | 537862a3b |
hex | 31f7c7a97 |
13413153431 has 2 divisors, whose sum is σ = 13413153432. Its totient is φ = 13413153430.
The previous prime is 13413153407. The next prime is 13413153461. The reversal of 13413153431 is 13435131431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13413153431 - 26 = 13413153367 is a prime.
It is a super-2 number, since 2×134131534312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13413153394 and 13413153403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13413153461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706576715 + 6706576716.
It is an arithmetic number, because the mean of its divisors is an integer number (6706576716).
Almost surely, 213413153431 is an apocalyptic number.
13413153431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13413153431 is an equidigital number, since it uses as much as digits as its factorization.
13413153431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 29.
Adding to 13413153431 its reverse (13435131431), we get a palindrome (26848284862).
The spelling of 13413153431 in words is "thirteen billion, four hundred thirteen million, one hundred fifty-three thousand, four hundred thirty-one".
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