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1341334041423 = 3447111347141
BaseRepresentation
bin10011100001001101101…
…111010011001101001111
311202020012212122022112020
4103201031233103031033
5133434023003311143
62504111135341223
7165623336142645
oct23411557231517
94666185568466
101341334041423
11477947109302
12197b62081813
139964467330c
1448cc6db9195
1524d57ac3883
hex1384dbd334f

1341334041423 has 4 divisors (see below), whose sum is σ = 1788445388568. Its totient is φ = 894222694280.

The previous prime is 1341334041401. The next prime is 1341334041427. The reversal of 1341334041423 is 3241404331431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1341334041423 - 28 = 1341334041167 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341334041427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223555673568 + ... + 223555673573.

It is an arithmetic number, because the mean of its divisors is an integer number (447111347142).

Almost surely, 21341334041423 is an apocalyptic number.

1341334041423 is a deficient number, since it is larger than the sum of its proper divisors (447111347145).

1341334041423 is an equidigital number, since it uses as much as digits as its factorization.

1341334041423 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447111347144.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1341334041423 its reverse (3241404331431), we get a palindrome (4582738372854).

The spelling of 1341334041423 in words is "one trillion, three hundred forty-one billion, three hundred thirty-four million, forty-one thousand, four hundred twenty-three".

Divisors: 1 3 447111347141 1341334041423