Base | Representation |
---|---|
bin | 1100001100110000110100… |
… | …0100010110110101011100 |
3 | 1202111022100001111200202210 |
4 | 3003030031010112311130 |
5 | 3224231121420030244 |
6 | 44310010514320420 |
7 | 2553041415514305 |
oct | 303141504266534 |
9 | 52438301450683 |
10 | 13413402111324 |
11 | 4301656894756 |
12 | 1607735289110 |
13 | 763b55a98a37 |
14 | 3452d81077ac |
15 | 183da79614b9 |
hex | c330d116d5c |
13413402111324 has 24 divisors (see below), whose sum is σ = 31300785646480. Its totient is φ = 4470727267584.
The previous prime is 13413402111199. The next prime is 13413402111391. The reversal of 13413402111324 is 42311120431431.
It is a super-2 number, since 2×134134021113242 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13413402111291 and 13413402111300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50708779 + ... + 50972610.
Almost surely, 213413402111324 is an apocalyptic number.
It is an amenable number.
13413402111324 is an abundant number, since it is smaller than the sum of its proper divisors (17887383535156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13413402111324 is a wasteful number, since it uses less digits than its factorization.
13413402111324 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101692389 (or 101692387 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 13413402111324 its reverse (42311120431431), we get a palindrome (55724522542755).
The spelling of 13413402111324 in words is "thirteen trillion, four hundred thirteen billion, four hundred two million, one hundred eleven thousand, three hundred twenty-four".
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