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1341413403 = 31140648891
BaseRepresentation
bin100111111110100…
…0101100000011011
310110111002212020220
41033331011200123
510221400212103
6341035051123
745145553151
oct11775054033
93414085226
101341413403
11629213820
123152a0aa3
13184ba7c55
14ca2213d1
157cb70c53
hex4ff4581b

1341413403 has 8 divisors (see below), whose sum is σ = 1951146816. Its totient is φ = 812977800.

The previous prime is 1341413401. The next prime is 1341413419. The reversal of 1341413403 is 3043141431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1341413403 - 21 = 1341413401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1341413401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20324413 + ... + 20324478.

It is an arithmetic number, because the mean of its divisors is an integer number (243893352).

Almost surely, 21341413403 is an apocalyptic number.

1341413403 is a deficient number, since it is larger than the sum of its proper divisors (609733413).

1341413403 is a wasteful number, since it uses less digits than its factorization.

1341413403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40648905.

The product of its (nonzero) digits is 1728, while the sum is 24.

The square root of 1341413403 is about 36625.3109611372. The cubic root of 1341413403 is about 1102.8612570694.

Adding to 1341413403 its reverse (3043141431), we get a palindrome (4384554834).

The spelling of 1341413403 in words is "one billion, three hundred forty-one million, four hundred thirteen thousand, four hundred three".

Divisors: 1 3 11 33 40648891 121946673 447137801 1341413403