Base | Representation |
---|---|
bin | 111110011101110001… |
… | …1010111101100010011 |
3 | 110211020122221020120121 |
4 | 1330323203113230103 |
5 | 4144211114122003 |
6 | 141342520251111 |
7 | 12456122440633 |
oct | 1747343275423 |
9 | 424218836517 |
10 | 134143114003 |
11 | 51987321a98 |
12 | 21bb8310a97 |
13 | c85a353a92 |
14 | 66c78346c3 |
15 | 3751957cbd |
hex | 1f3b8d7b13 |
134143114003 has 4 divisors (see below), whose sum is σ = 136674116208. Its totient is φ = 131612111800.
The previous prime is 134143113991. The next prime is 134143114033. The reversal of 134143114003 is 300411341431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300411341431 = 241469 ⋅1244099.
It is a cyclic number.
It is not a de Polignac number, because 134143114003 - 221 = 134141016851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134143114033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1265501023 + ... + 1265501128.
It is an arithmetic number, because the mean of its divisors is an integer number (34168529052).
Almost surely, 2134143114003 is an apocalyptic number.
134143114003 is a deficient number, since it is larger than the sum of its proper divisors (2531002205).
134143114003 is an equidigital number, since it uses as much as digits as its factorization.
134143114003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2531002204.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 134143114003 its reverse (300411341431), we get a palindrome (434554455434).
The spelling of 134143114003 in words is "one hundred thirty-four billion, one hundred forty-three million, one hundred fourteen thousand, three".
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