134144521433 has 4 divisors (see below), whose sum is σ = 144463330788. Its totient is φ = 123825712080.

The previous prime is 134144521421. The next prime is 134144521439. The reversal of 134144521433 is 334125441431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334125441431 = 19 ⋅17585549549.

It can be written as a sum of positive squares in 2 ways, for example, as 76346110864 + 57798410569 = 276308^2 + 240413^2 .

It is a cyclic number.

It is not a de Polignac number, because 134144521433 - 2⁸ = 134144521177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134144521393 and 134144521402.

It is not an unprimeable number, because it can be changed into a prime (134144521439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5159404658 + ... + 5159404683.

It is an arithmetic number, because the mean of its divisors is an integer number (36115832697).

Almost surely, 2^134144521433 is an apocalyptic number.

134144521433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

134144521433 is a deficient number, since it is larger than the sum of its proper divisors (10318809355).

134144521433 is a wasteful number, since it uses less digits than its factorization.

134144521433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10318809354.

The product of its digits is 69120, while the sum is 35.

Adding to 134144521433 its reverse (334125441431), we get a palindrome (468269962864).

The spelling of 134144521433 in words is "one hundred thirty-four billion, one hundred forty-four million, five hundred twenty-one thousand, four hundred thirty-three".