13415043339947 has 2 divisors, whose sum is σ = 13415043339948. Its totient is φ = 13415043339946.

The previous prime is 13415043339941. The next prime is 13415043340043. The reversal of 13415043339947 is 74993334051431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13415043339947 - 2⁶ = 13415043339883 is a prime.

It is a super-2 number, since 2×13415043339947² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13415043339892 and 13415043339901.

It is not a weakly prime, because it can be changed into another prime (13415043339941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707521669973 + 6707521669974.

It is an arithmetic number, because the mean of its divisors is an integer number (6707521669974).

Almost surely, 2^{13415043339947} is an apocalyptic number.

13415043339947 is a deficient number, since it is larger than the sum of its proper divisors (1).

13415043339947 is an equidigital number, since it uses as much as digits as its factorization.

13415043339947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14696640, while the sum is 56.

The spelling of 13415043339947 in words is "thirteen trillion, four hundred fifteen billion, forty-three million, three hundred thirty-nine thousand, nine hundred forty-seven".