Base | Representation |
---|---|
bin | 1100001100110110111011… |
… | …1001001001011100001011 |
3 | 1202111110120102202202022122 |
4 | 3003031232321021130023 |
5 | 3224243002043340133 |
6 | 44310441423441455 |
7 | 2553130164650552 |
oct | 303155671113413 |
9 | 52443512682278 |
10 | 13415043340043 |
11 | 4302319266124 |
12 | 1607b12a5628b |
13 | 764057b086a7 |
14 | 345412090d99 |
15 | 183e51aa6498 |
hex | c336ee4970b |
13415043340043 has 2 divisors, whose sum is σ = 13415043340044. Its totient is φ = 13415043340042.
The previous prime is 13415043339947. The next prime is 13415043340063. The reversal of 13415043340043 is 34004334051431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13415043340043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13415043339985 and 13415043340012.
It is not a weakly prime, because it can be changed into another prime (13415043340063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707521670021 + 6707521670022.
It is an arithmetic number, because the mean of its divisors is an integer number (6707521670022).
Almost surely, 213415043340043 is an apocalyptic number.
13415043340043 is a deficient number, since it is larger than the sum of its proper divisors (1).
13415043340043 is an equidigital number, since it uses as much as digits as its factorization.
13415043340043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 13415043340043 its reverse (34004334051431), we get a palindrome (47419377391474).
The spelling of 13415043340043 in words is "thirteen trillion, four hundred fifteen billion, forty-three million, three hundred forty thousand, forty-three".
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