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13415043339941 is a prime number
BaseRepresentation
bin1100001100110110111011…
…1001001001011010100101
31202111110120102202202011212
43003031232321021122211
53224243002043334231
644310441423441205
72553130164650345
oct303155671113245
952443512682155
1013415043339941
114302319266041
121607b12a56205
13764057b08629
14345412090d25
15183e51aa642b
hexc336ee496a5

13415043339941 has 2 divisors, whose sum is σ = 13415043339942. Its totient is φ = 13415043339940.

The previous prime is 13415043339937. The next prime is 13415043339947. The reversal of 13415043339941 is 14993334051431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13408266592900 + 6776747041 = 3661730^2 + 82321^2 .

It is a cyclic number.

It is not a de Polignac number, because 13415043339941 - 22 = 13415043339937 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13415043339941.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13415043339947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6707521669970 + 6707521669971.

It is an arithmetic number, because the mean of its divisors is an integer number (6707521669971).

Almost surely, 213415043339941 is an apocalyptic number.

It is an amenable number.

13415043339941 is a deficient number, since it is larger than the sum of its proper divisors (1).

13415043339941 is an equidigital number, since it uses as much as digits as its factorization.

13415043339941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2099520, while the sum is 50.

The spelling of 13415043339941 in words is "thirteen trillion, four hundred fifteen billion, forty-three million, three hundred thirty-nine thousand, nine hundred forty-one".