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134152132202455 = 526830426440491
BaseRepresentation
bin11110100000001010111010…
…001011111000111111010111
3122120222211002202021121110211
4132200022322023320333113
5120040422031320434310
61153152345545030251
740154112616123543
oct3640127213707727
9576884082247424
10134152132202455
1139821666320234
12130676b9785387
1359b16515b4513
14251add811ca23
15107991140bc8a
hex7a02ba2f8fd7

134152132202455 has 4 divisors (see below), whose sum is σ = 160982558642952. Its totient is φ = 107321705761960.

The previous prime is 134152132202419. The next prime is 134152132202467. The reversal of 134152132202455 is 554202231251431.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-134152132202455 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13415213220241 + ... + 13415213220250.

It is an arithmetic number, because the mean of its divisors is an integer number (40245639660738).

Almost surely, 2134152132202455 is an apocalyptic number.

134152132202455 is a deficient number, since it is larger than the sum of its proper divisors (26830426440497).

134152132202455 is an equidigital number, since it uses as much as digits as its factorization.

134152132202455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26830426440496.

The product of its (nonzero) digits is 288000, while the sum is 40.

Adding to 134152132202455 its reverse (554202231251431), we get a palindrome (688354363453886).

The spelling of 134152132202455 in words is "one hundred thirty-four trillion, one hundred fifty-two billion, one hundred thirty-two million, two hundred two thousand, four hundred fifty-five".

Divisors: 1 5 26830426440491 134152132202455