1341755340231 has 4 divisors (see below), whose sum is σ = 1789007120312. Its totient is φ = 894503560152.

The previous prime is 1341755340229. The next prime is 1341755340241. The reversal of 1341755340231 is 1320435571431.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1341755340231 - 2¹ = 1341755340229 is a prime.

It is a super-2 number, since 2×1341755340231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1341755340231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341755340221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223625890036 + ... + 223625890041.

It is an arithmetic number, because the mean of its divisors is an integer number (447251780078).

Almost surely, 2^{1341755340231} is an apocalyptic number.

1341755340231 is a deficient number, since it is larger than the sum of its proper divisors (447251780081).

1341755340231 is an equidigital number, since it uses as much as digits as its factorization.

1341755340231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 447251780080.

The product of its (nonzero) digits is 151200, while the sum is 39.

The spelling of 1341755340231 in words is "one trillion, three hundred forty-one billion, seven hundred fifty-five million, three hundred forty thousand, two hundred thirty-one".