Base | Representation |
---|---|
bin | 10011100001110101011… |
… | …100111011011110111110 |
3 | 11202021221022100111002112 |
4 | 103201311130323132332 |
5 | 133441404040024202 |
6 | 2504301220054022 |
7 | 165646006313324 |
oct | 23416534733676 |
9 | 4667838314075 |
10 | 1342000314302 |
11 | 478159211a4a |
12 | 198109234312 |
13 | 9971c70411b |
14 | 48d4b693d14 |
15 | 24d96332b52 |
hex | 1387573b7be |
1342000314302 has 4 divisors (see below), whose sum is σ = 2013000471456. Its totient is φ = 671000157150.
The previous prime is 1342000314283. The next prime is 1342000314353. The reversal of 1342000314302 is 2034130002431.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 335500078574 + ... + 335500078577.
It is an arithmetic number, because the mean of its divisors is an integer number (503250117864).
Almost surely, 21342000314302 is an apocalyptic number.
1342000314302 is a deficient number, since it is larger than the sum of its proper divisors (671000157154).
1342000314302 is an equidigital number, since it uses as much as digits as its factorization.
1342000314302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 671000157153.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 1342000314302 its reverse (2034130002431), we get a palindrome (3376130316733).
The spelling of 1342000314302 in words is "one trillion, three hundred forty-two billion, three hundred fourteen thousand, three hundred two".
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