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134210000143 = 6531201171131
BaseRepresentation
bin111110011111110001…
…0100001010100001111
3110211102022210102010001
41330333202201110033
54144330230001033
6141353310025131
712460564115152
oct1747742412417
9424368712101
10134210000143
1151a1105659a
12220167a81a7
13c86b17218b
1466d2685c99
15375776ae7d
hex1f3f8a150f

134210000143 has 8 divisors (see below), whose sum is σ = 134528234256. Its totient is φ = 133892112000.

The previous prime is 134210000059. The next prime is 134210000167. The reversal of 134210000143 is 341000012431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134210000143 - 217 = 134209869071 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 134210000143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134210004143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 698688 + ... + 869818.

It is an arithmetic number, because the mean of its divisors is an integer number (16816029282).

Almost surely, 2134210000143 is an apocalyptic number.

134210000143 is a deficient number, since it is larger than the sum of its proper divisors (318234113).

134210000143 is a wasteful number, since it uses less digits than its factorization.

134210000143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 172985.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 134210000143 its reverse (341000012431), we get a palindrome (475210012574).

The spelling of 134210000143 in words is "one hundred thirty-four billion, two hundred ten million, one hundred forty-three", and thus it is an aban number.

Divisors: 1 653 1201 171131 784253 111748543 205528331 134210000143