Search a number
-
+
13421000063 is a prime number
BaseRepresentation
bin11000111111111010…
…00011010101111111
31021122022222102222102
430133331003111333
5204441234000223
610055430335315
7653404422032
oct143775032577
937568872872
1013421000063
115767893a99
1227267ba53b
13135b686973
14914639019
155383b2928
hex31ff4357f

13421000063 has 2 divisors, whose sum is σ = 13421000064. Its totient is φ = 13421000062.

The previous prime is 13421000057. The next prime is 13421000137. The reversal of 13421000063 is 36000012431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13421000063 - 214 = 13420983679 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13420999999 and 13421000044.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13421000363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710500031 + 6710500032.

It is an arithmetic number, because the mean of its divisors is an integer number (6710500032).

Almost surely, 213421000063 is an apocalyptic number.

13421000063 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421000063 is an equidigital number, since it uses as much as digits as its factorization.

13421000063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13421000063 its reverse (36000012431), we get a palindrome (49421012494).

The spelling of 13421000063 in words is "thirteen billion, four hundred twenty-one million, sixty-three", and thus it is an aban number.