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1342101151 is a prime number
BaseRepresentation
bin100111111111110…
…1101011010011111
310110112101210200001
41033333231122133
510222034214101
6341101515131
745154446226
oct11777553237
93415353601
101342101151
11629643506
12315572aa7
13185088cc1
14ca35dcbd
157cc59901
hex4ffed69f

1342101151 has 2 divisors, whose sum is σ = 1342101152. Its totient is φ = 1342101150.

The previous prime is 1342101127. The next prime is 1342101161. The reversal of 1342101151 is 1511012431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1342101151 - 211 = 1342099103 is a prime.

It is a super-3 number, since 3×13421011513 (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342101161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671050575 + 671050576.

It is an arithmetic number, because the mean of its divisors is an integer number (671050576).

Almost surely, 21342101151 is an apocalyptic number.

1342101151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342101151 is an equidigital number, since it uses as much as digits as its factorization.

1342101151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 1342101151 is about 36634.6987294832. The cubic root of 1342101151 is about 1103.0497053215.

Adding to 1342101151 its reverse (1511012431), we get a palindrome (2853113582).

The spelling of 1342101151 in words is "one billion, three hundred forty-two million, one hundred one thousand, one hundred fifty-one".