Base | Representation |
---|---|
bin | 1100001101001101010001… |
… | …0101000001010111100100 |
3 | 1202112001001100202101111100 |
4 | 3003103110111001113210 |
5 | 3224342242232104444 |
6 | 44313312443240100 |
7 | 2553431612456160 |
oct | 303232425012744 |
9 | 52461040671440 |
10 | 13421040113124 |
11 | 4304916292536 |
12 | 1609107219030 |
13 | 7647a2314727 |
14 | 34582069dca0 |
15 | 1841a32a2e69 |
hex | c34d45415e4 |
13421040113124 has 144 divisors (see below), whose sum is σ = 38927080902528. Its totient is φ = 3819255197184.
The previous prime is 13421040113051. The next prime is 13421040113213. The reversal of 13421040113124 is 42131104012431.
It is a happy number.
13421040113124 is a `hidden beast` number, since 1 + 3 + 421 + 0 + 4 + 0 + 113 + 124 = 666.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 95231199 + ... + 95372025.
It is an arithmetic number, because the mean of its divisors is an integer number (270326950712).
Almost surely, 213421040113124 is an apocalyptic number.
13421040113124 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13421040113124, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19463540451264).
13421040113124 is an abundant number, since it is smaller than the sum of its proper divisors (25506040789404).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13421040113124 is a wasteful number, since it uses less digits than its factorization.
13421040113124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142354 (or 142349 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 27.
Adding to 13421040113124 its reverse (42131104012431), we get a palindrome (55552144125555).
The spelling of 13421040113124 in words is "thirteen trillion, four hundred twenty-one billion, forty million, one hundred thirteen thousand, one hundred twenty-four".
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