13421110015 has 4 divisors (see below), whose sum is σ = 16105332024. Its totient is φ = 10736888008.

The previous prime is 13421109967. The next prime is 13421110039. The reversal of 13421110015 is 51001112431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 51001112431 = 4643 ⋅10984517.

It is a cyclic number.

It is not a de Polignac number, because 13421110015 - 2²³ = 13412721407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13421109974 and 13421110001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1342110997 + ... + 1342111006.

It is an arithmetic number, because the mean of its divisors is an integer number (4026333006).

Almost surely, 2^13421110015 is an apocalyptic number.

13421110015 is a deficient number, since it is larger than the sum of its proper divisors (2684222009).

13421110015 is an equidigital number, since it uses as much as digits as its factorization.

13421110015 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2684222008.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 13421110015 its reverse (51001112431), we get a palindrome (64422222446).

The spelling of 13421110015 in words is "thirteen billion, four hundred twenty-one million, one hundred ten thousand, fifteen".