Base | Representation |
---|---|
bin | 111110011111110011… |
… | …1100010001000110111 |
3 | 110211102102021011200222 |
4 | 1330333213202020313 |
5 | 4144331044023411 |
6 | 141353354124555 |
7 | 12460611230261 |
oct | 1747747421067 |
9 | 424372234628 |
10 | 134211314231 |
11 | 51a11873915 |
12 | 2201712075b |
13 | c86b512347 |
14 | 66d2908b31 |
15 | 375792a4db |
hex | 1f3f9e2237 |
134211314231 has 2 divisors, whose sum is σ = 134211314232. Its totient is φ = 134211314230.
The previous prime is 134211314207. The next prime is 134211314243. The reversal of 134211314231 is 132413112431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134211314231 is a prime.
It is a super-2 number, since 2×1342113142312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 134211314231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134211314291) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67105657115 + 67105657116.
It is an arithmetic number, because the mean of its divisors is an integer number (67105657116).
Almost surely, 2134211314231 is an apocalyptic number.
134211314231 is a deficient number, since it is larger than the sum of its proper divisors (1).
134211314231 is an equidigital number, since it uses as much as digits as its factorization.
134211314231 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1728, while the sum is 26.
Adding to 134211314231 its reverse (132413112431), we get a palindrome (266624426662).
The spelling of 134211314231 in words is "one hundred thirty-four billion, two hundred eleven million, three hundred fourteen thousand, two hundred thirty-one".
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