13421413223081 has 2 divisors, whose sum is σ = 13421413223082. Its totient is φ = 13421413223080.

The previous prime is 13421413223011. The next prime is 13421413223083. The reversal of 13421413223081 is 18032231412431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12594797677225 + 826615545856 = 3548915^2 + 909184^2 .

It is an emirp because it is prime and its reverse (18032231412431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13421413223081 - 2¹⁰ = 13421413222057 is a prime.

It is a super-3 number, since 3×13421413223081³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13421413223083, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13421413223083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710706611540 + 6710706611541.

It is an arithmetic number, because the mean of its divisors is an integer number (6710706611541).

Almost surely, 2^{13421413223081} is an apocalyptic number.

It is an amenable number.

13421413223081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421413223081 is an equidigital number, since it uses as much as digits as its factorization.

13421413223081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 13421413223081 in words is "thirteen trillion, four hundred twenty-one billion, four hundred thirteen million, two hundred twenty-three thousand, eighty-one".