Base | Representation |
---|---|
bin | 11110100001000101101010… |
… | …101001100100000010011111 |
3 | 122121012211221121110022011011 |
4 | 132201011222221210002133 |
5 | 120042440233403004434 |
6 | 1153241342201040051 |
7 | 40161505220200333 |
oct | 3641055251440237 |
9 | 577184847408134 |
10 | 134215222313119 |
11 | 398463a1015162 |
12 | 13077986486027 |
13 | 59b75972b634c |
14 | 25200a11537c3 |
15 | 107b3a50a2e64 |
hex | 7a116aa6409f |
134215222313119 has 2 divisors, whose sum is σ = 134215222313120. Its totient is φ = 134215222313118.
The previous prime is 134215222313101. The next prime is 134215222313153. The reversal of 134215222313119 is 911313222512431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134215222313119 - 229 = 134214685442207 is a prime.
It is a super-2 number, since 2×1342152223131192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134215222313819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67107611156559 + 67107611156560.
It is an arithmetic number, because the mean of its divisors is an integer number (67107611156560).
Almost surely, 2134215222313119 is an apocalyptic number.
134215222313119 is a deficient number, since it is larger than the sum of its proper divisors (1).
134215222313119 is an equidigital number, since it uses as much as digits as its factorization.
134215222313119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 40.
The spelling of 134215222313119 in words is "one hundred thirty-four trillion, two hundred fifteen billion, two hundred twenty-two million, three hundred thirteen thousand, one hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •