Base | Representation |
---|---|
bin | 111110011111111101… |
… | …0000000010011111101 |
3 | 110211102202101011221001 |
4 | 1330333322000103331 |
5 | 4144333314001123 |
6 | 141354050010301 |
7 | 12461000335363 |
oct | 1747772002375 |
9 | 424382334831 |
10 | 134216156413 |
11 | 51a14580919 |
12 | 22018876991 |
13 | c86c519341 |
14 | 66d3409633 |
15 | 37580850ad |
hex | 1f3fe804fd |
134216156413 has 2 divisors, whose sum is σ = 134216156414. Its totient is φ = 134216156412.
The previous prime is 134216156317. The next prime is 134216156443. The reversal of 134216156413 is 314651612431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100487732004 + 33728424409 = 316998^2 + 183653^2 .
It is a cyclic number.
It is not a de Polignac number, because 134216156413 - 217 = 134216025341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134216156443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67108078206 + 67108078207.
It is an arithmetic number, because the mean of its divisors is an integer number (67108078207).
Almost surely, 2134216156413 is an apocalyptic number.
It is an amenable number.
134216156413 is a deficient number, since it is larger than the sum of its proper divisors (1).
134216156413 is an equidigital number, since it uses as much as digits as its factorization.
134216156413 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51840, while the sum is 37.
Adding to 134216156413 its reverse (314651612431), we get a palindrome (448867768844).
The spelling of 134216156413 in words is "one hundred thirty-four billion, two hundred sixteen million, one hundred fifty-six thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •