Search a number
-
+
134216156413 is a prime number
BaseRepresentation
bin111110011111111101…
…0000000010011111101
3110211102202101011221001
41330333322000103331
54144333314001123
6141354050010301
712461000335363
oct1747772002375
9424382334831
10134216156413
1151a14580919
1222018876991
13c86c519341
1466d3409633
1537580850ad
hex1f3fe804fd

134216156413 has 2 divisors, whose sum is σ = 134216156414. Its totient is φ = 134216156412.

The previous prime is 134216156317. The next prime is 134216156443. The reversal of 134216156413 is 314651612431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100487732004 + 33728424409 = 316998^2 + 183653^2 .

It is a cyclic number.

It is not a de Polignac number, because 134216156413 - 217 = 134216025341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134216156443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67108078206 + 67108078207.

It is an arithmetic number, because the mean of its divisors is an integer number (67108078207).

Almost surely, 2134216156413 is an apocalyptic number.

It is an amenable number.

134216156413 is a deficient number, since it is larger than the sum of its proper divisors (1).

134216156413 is an equidigital number, since it uses as much as digits as its factorization.

134216156413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 51840, while the sum is 37.

Adding to 134216156413 its reverse (314651612431), we get a palindrome (448867768844).

The spelling of 134216156413 in words is "one hundred thirty-four billion, two hundred sixteen million, one hundred fifty-six thousand, four hundred thirteen".