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13421800674047 is a prime number
BaseRepresentation
bin1100001101010000000110…
…1010010101001011111111
31202112010000100212212221102
43003110001222111023333
53224400321433032142
644313520132523315
72553456506232023
oct303240152251377
952463010785842
1013421800674047
114305176636187
121609299a8053b
13764893a6918c
143458936c0383
151841e9e39532
hexc3501a952ff

13421800674047 has 2 divisors, whose sum is σ = 13421800674048. Its totient is φ = 13421800674046.

The previous prime is 13421800673959. The next prime is 13421800674049. The reversal of 13421800674047 is 74047600812431.

13421800674047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13421800674047 - 214 = 13421800657663 is a prime.

Together with 13421800674049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13421800673992 and 13421800674010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13421800674049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6710900337023 + 6710900337024.

It is an arithmetic number, because the mean of its divisors is an integer number (6710900337024).

Almost surely, 213421800674047 is an apocalyptic number.

13421800674047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13421800674047 is an equidigital number, since it uses as much as digits as its factorization.

13421800674047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 903168, while the sum is 47.

The spelling of 13421800674047 in words is "thirteen trillion, four hundred twenty-one billion, eight hundred million, six hundred seventy-four thousand, forty-seven".