Base | Representation |
---|---|
bin | 1100001101010000111011… |
… | …0111110011100011100011 |
3 | 1202112010120210221011110200 |
4 | 3003110032313303203203 |
5 | 3224401300202410430 |
6 | 44313554131200243 |
7 | 2553465140141226 |
oct | 303241667634343 |
9 | 52463523834420 |
10 | 13422022310115 |
11 | 430527a756691 |
12 | 1609340146083 |
13 | 7648ca95a493 |
14 | 3458b4cd55bd |
15 | 18420e619460 |
hex | c350edf38e3 |
13422022310115 has 12 divisors (see below), whose sum is σ = 23264838670944. Its totient is φ = 7158411898704.
The previous prime is 13422022310083. The next prime is 13422022310149. The reversal of 13422022310115 is 51101322022431.
It is a happy number.
13422022310115 is a `hidden beast` number, since 1 + 3 + 422 + 0 + 2 + 231 + 0 + 1 + 1 + 5 = 666.
It is not a de Polignac number, because 13422022310115 - 25 = 13422022310083 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 149133581179 + ... + 149133581268.
It is an arithmetic number, because the mean of its divisors is an integer number (1938736555912).
Almost surely, 213422022310115 is an apocalyptic number.
13422022310115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13422022310115 is a deficient number, since it is larger than the sum of its proper divisors (9842816360829).
13422022310115 is a wasteful number, since it uses less digits than its factorization.
13422022310115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298267162458 (or 298267162455 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 13422022310115 its reverse (51101322022431), we get a palindrome (64523344332546).
The spelling of 13422022310115 in words is "thirteen trillion, four hundred twenty-two billion, twenty-two million, three hundred ten thousand, one hundred fifteen".
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