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134223231040132 = 221316715456383123
BaseRepresentation
bin11110100001001101001000…
…000000011011101010000100
3122121020121121202021210021011
4132201031020000123222010
5120043103134121241012
61153245145011532004
740162210535225563
oct3641151000335204
9577217552253234
10134223231040132
1139849830803313
12130794405ba004
1359b8272593780
142520620a4dbda
15107b6c32241a7
hex7a134801ba84

134223231040132 has 24 divisors (see below), whose sum is σ = 254473891753536. Its totient is φ = 61578230358048.

The previous prime is 134223231040097. The next prime is 134223231040141. The reversal of 134223231040132 is 231040132322431.

It is a junction number, because it is equal to n+sod(n) for n = 134223231040094 and 134223231040103.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7728182878 + ... + 7728200245.

It is an arithmetic number, because the mean of its divisors is an integer number (10603078823064).

Almost surely, 2134223231040132 is an apocalyptic number.

It is an amenable number.

134223231040132 is a deficient number, since it is larger than the sum of its proper divisors (120250660713404).

134223231040132 is a wasteful number, since it uses less digits than its factorization.

134223231040132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15456383307 (or 15456383305 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 134223231040132 its reverse (231040132322431), we get a palindrome (365263363362563).

The spelling of 134223231040132 in words is "one hundred thirty-four trillion, two hundred twenty-three billion, two hundred thirty-one million, forty thousand, one hundred thirty-two".

Divisors: 1 2 4 13 26 52 167 334 668 2171 4342 8684 15456383123 30912766246 61825532492 200932980599 401865961198 803731922396 2581215981541 5162431963082 10324863926164 33555807760033 67111615520066 134223231040132