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1342251005309 is a prime number
BaseRepresentation
bin10011100010000100011…
…001001111010101111101
311202022120210001220111122
4103202010121033111331
5133442412224132214
62504342133200325
7165655142204024
oct23420431172575
94668523056448
101342251005309
114782777778a5
121981791900a5
139975c6291b6
1448d72aad8bb
1524dad35188e
hex1388464f57d

1342251005309 has 2 divisors, whose sum is σ = 1342251005310. Its totient is φ = 1342251005308.

The previous prime is 1342251005273. The next prime is 1342251005311. The reversal of 1342251005309 is 9035001522431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1318466580025 + 23784425284 = 1148245^2 + 154222^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1342251005309 is a prime.

It is a super-2 number, since 2×13422510053092 (a number of 25 digits) contains 22 as substring.

Together with 1342251005311, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342251005369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671125502654 + 671125502655.

It is an arithmetic number, because the mean of its divisors is an integer number (671125502655).

Almost surely, 21342251005309 is an apocalyptic number.

It is an amenable number.

1342251005309 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342251005309 is an equidigital number, since it uses as much as digits as its factorization.

1342251005309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 1342251005309 in words is "one trillion, three hundred forty-two billion, two hundred fifty-one million, five thousand, three hundred nine".