Base | Representation |
---|---|
bin | 10011100010000111100… |
… | …001010111001001000111 |
3 | 11202022201102210012010020 |
4 | 103202013201113021013 |
5 | 133443014141403210 |
6 | 2504351245430223 |
7 | 165656350130556 |
oct | 23420741271107 |
9 | 4668642705106 |
10 | 1342303466055 |
11 | 4782a4349392 |
12 | 19819286b373 |
13 | 9976a466666 |
14 | 48d79a47d9d |
15 | 24db2c65770 |
hex | 13887857247 |
1342303466055 has 128 divisors (see below), whose sum is σ = 2428556774400. Its totient is φ = 629092122624.
The previous prime is 1342303466039. The next prime is 1342303466117. The reversal of 1342303466055 is 5506643032431.
It is not a de Polignac number, because 1342303466055 - 24 = 1342303466039 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1342303465998 and 1342303466016.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 97992967 + ... + 98006663.
It is an arithmetic number, because the mean of its divisors is an integer number (18973099800).
Almost surely, 21342303466055 is an apocalyptic number.
1342303466055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1342303466055 is a deficient number, since it is larger than the sum of its proper divisors (1086253308345).
1342303466055 is a wasteful number, since it uses less digits than its factorization.
1342303466055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14033.
The product of its (nonzero) digits is 777600, while the sum is 42.
Adding to 1342303466055 its reverse (5506643032431), we get a palindrome (6848946498486).
The spelling of 1342303466055 in words is "one trillion, three hundred forty-two billion, three hundred three million, four hundred sixty-six thousand, fifty-five".
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