Base | Representation |
---|---|
bin | 11001000000001010… |
… | …01001111001010011 |
3 | 1021122110222100112122 |
4 | 30200011021321103 |
5 | 204442304432201 |
6 | 10055544044455 |
7 | 653431446311 |
oct | 144005117123 |
9 | 37573870478 |
10 | 13423124051 |
11 | 5769004857 |
12 | 272746372b |
13 | 135bc4b66c |
14 | 914a2d0b1 |
15 | 538681e1b |
hex | 320149e53 |
13423124051 has 2 divisors, whose sum is σ = 13423124052. Its totient is φ = 13423124050.
The previous prime is 13423124041. The next prime is 13423124053. The reversal of 13423124051 is 15042132431.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13423124051 is a prime.
Together with 13423124053, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13423124051.
It is not a weakly prime, because it can be changed into another prime (13423124053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6711562025 + 6711562026.
It is an arithmetic number, because the mean of its divisors is an integer number (6711562026).
Almost surely, 213423124051 is an apocalyptic number.
13423124051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13423124051 is an equidigital number, since it uses as much as digits as its factorization.
13423124051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 13423124051 its reverse (15042132431), we get a palindrome (28465256482).
The spelling of 13423124051 in words is "thirteen billion, four hundred twenty-three million, one hundred twenty-four thousand, fifty-one".
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