13423424011141 has 4 divisors (see below), whose sum is σ = 13423457979072. Its totient is φ = 13423390043212.

The previous prime is 13423424011043. The next prime is 13423424011163. The reversal of 13423424011141 is 14111042432431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13423424011141 - 2⁷ = 13423424011013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13423424011181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16384135 + ... + 17183908.

It is an arithmetic number, because the mean of its divisors is an integer number (3355864494768).

Almost surely, 2^{13423424011141} is an apocalyptic number.

It is an amenable number.

13423424011141 is a deficient number, since it is larger than the sum of its proper divisors (33967931).

13423424011141 is an equidigital number, since it uses as much as digits as its factorization.

13423424011141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33967930.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 13423424011141 its reverse (14111042432431), we get a palindrome (27534466443572).

The spelling of 13423424011141 in words is "thirteen trillion, four hundred twenty-three billion, four hundred twenty-four million, eleven thousand, one hundred forty-one".