Base | Representation |
---|---|
bin | 111110100000101010… |
… | …1000011011000110001 |
3 | 110211111102021210020221 |
4 | 1331001111003120301 |
5 | 4144410421232423 |
6 | 141400301333041 |
7 | 12461410243456 |
oct | 1750125033061 |
9 | 424442253227 |
10 | 134240024113 |
11 | 51a26aa2a98 |
12 | 22024867181 |
13 | c874455040 |
14 | 66d665d82d |
15 | 375a1ebe5d |
hex | 1f41543631 |
134240024113 has 16 divisors (see below), whose sum is σ = 154669614400. Its totient is φ = 115467612480.
The previous prime is 134240024111. The next prime is 134240024123. The reversal of 134240024113 is 311420042431.
It is not a de Polignac number, because 134240024113 - 21 = 134240024111 is a prime.
It is a super-4 number, since 4×1342400241134 (a number of 46 digits) contains 4444 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134240024111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4439703 + ... + 4469836.
It is an arithmetic number, because the mean of its divisors is an integer number (9666850900).
Almost surely, 2134240024113 is an apocalyptic number.
134240024113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
134240024113 is a deficient number, since it is larger than the sum of its proper divisors (20429590287).
134240024113 is a wasteful number, since it uses less digits than its factorization.
134240024113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8909632.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 134240024113 its reverse (311420042431), we get a palindrome (445660066544).
The spelling of 134240024113 in words is "one hundred thirty-four billion, two hundred forty million, twenty-four thousand, one hundred thirteen".
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