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13424245103 is a prime number
BaseRepresentation
bin11001000000010010…
…11011100101101111
31021122120002022100002
430200021123211233
5204443101320403
610100024054515
7653444125553
oct144011334557
937576068302
1013424245103
115769700045
12272790443b
13135c2519c9
14914c41863
15538804188
hex32025b96f

13424245103 has 2 divisors, whose sum is σ = 13424245104. Its totient is φ = 13424245102.

The previous prime is 13424245099. The next prime is 13424245127. The reversal of 13424245103 is 30154242431.

13424245103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13424245103 - 22 = 13424245099 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13424245193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712122551 + 6712122552.

It is an arithmetic number, because the mean of its divisors is an integer number (6712122552).

Almost surely, 213424245103 is an apocalyptic number.

13424245103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13424245103 is an equidigital number, since it uses as much as digits as its factorization.

13424245103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13424245103 its reverse (30154242431), we get a palindrome (43578487534).

The spelling of 13424245103 in words is "thirteen billion, four hundred twenty-four million, two hundred forty-five thousand, one hundred three".