Base | Representation |
---|---|
bin | 11001000000010010… |
… | …11011100101101111 |
3 | 1021122120002022100002 |
4 | 30200021123211233 |
5 | 204443101320403 |
6 | 10100024054515 |
7 | 653444125553 |
oct | 144011334557 |
9 | 37576068302 |
10 | 13424245103 |
11 | 5769700045 |
12 | 272790443b |
13 | 135c2519c9 |
14 | 914c41863 |
15 | 538804188 |
hex | 32025b96f |
13424245103 has 2 divisors, whose sum is σ = 13424245104. Its totient is φ = 13424245102.
The previous prime is 13424245099. The next prime is 13424245127. The reversal of 13424245103 is 30154242431.
13424245103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13424245103 - 22 = 13424245099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13424245193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712122551 + 6712122552.
It is an arithmetic number, because the mean of its divisors is an integer number (6712122552).
Almost surely, 213424245103 is an apocalyptic number.
13424245103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13424245103 is an equidigital number, since it uses as much as digits as its factorization.
13424245103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13424245103 its reverse (30154242431), we get a palindrome (43578487534).
The spelling of 13424245103 in words is "thirteen billion, four hundred twenty-four million, two hundred forty-five thousand, one hundred three".
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