Base | Representation |
---|---|
bin | 111110100000110000… |
… | …1001001101000010101 |
3 | 110211111122020220110111 |
4 | 1331001201021220111 |
5 | 4144412224223123 |
6 | 141400453323021 |
7 | 12461446222315 |
oct | 1750141115025 |
9 | 424448226414 |
10 | 134243195413 |
11 | 51a288696a8 |
12 | 22025936471 |
13 | c874cc5652 |
14 | 66d6c47445 |
15 | 375a62690d |
hex | 1f41849a15 |
134243195413 has 2 divisors, whose sum is σ = 134243195414. Its totient is φ = 134243195412.
The previous prime is 134243195377. The next prime is 134243195431. The reversal of 134243195413 is 314591342431.
It is a happy number.
Together with next prime (134243195431) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96831125329 + 37412070084 = 311177^2 + 193422^2 .
It is a cyclic number.
It is not a de Polignac number, because 134243195413 - 29 = 134243194901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134243195813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67121597706 + 67121597707.
It is an arithmetic number, because the mean of its divisors is an integer number (67121597707).
Almost surely, 2134243195413 is an apocalyptic number.
It is an amenable number.
134243195413 is a deficient number, since it is larger than the sum of its proper divisors (1).
134243195413 is an equidigital number, since it uses as much as digits as its factorization.
134243195413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 40.
The spelling of 134243195413 in words is "one hundred thirty-four billion, two hundred forty-three million, one hundred ninety-five thousand, four hundred thirteen".
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