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13424425325497 = 71511877279447
BaseRepresentation
bin1100001101011001111000…
…0110100101001110111001
31202112100210021121222212101
43003112132012211032321
53224421210340403442
644315032412143401
72553611526344044
oct303263606451671
952470707558771
1013424425325497
1143062a313870a
1216098b0a67b61
13764bc1760784
14345a620dbc5b
15184300588cb7
hexc359e1a53b9

13424425325497 has 4 divisors (see below), whose sum is σ = 13426302612096. Its totient is φ = 13422548038900.

The previous prime is 13424425325449. The next prime is 13424425325551. The reversal of 13424425325497 is 79452352442431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13424425325497 - 27 = 13424425325369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13424425326497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 938632573 + ... + 938646874.

It is an arithmetic number, because the mean of its divisors is an integer number (3356575653024).

Almost surely, 213424425325497 is an apocalyptic number.

It is an amenable number.

13424425325497 is a deficient number, since it is larger than the sum of its proper divisors (1877286599).

13424425325497 is an equidigital number, since it uses as much as digits as its factorization.

13424425325497 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1877286598.

The product of its digits is 29030400, while the sum is 55.

The spelling of 13424425325497 in words is "thirteen trillion, four hundred twenty-four billion, four hundred twenty-five million, three hundred twenty-five thousand, four hundred ninety-seven".

Divisors: 1 7151 1877279447 13424425325497