Base | Representation |
---|---|
bin | 11001000000010100… |
… | …00111101000101001 |
3 | 1021122120102110210221 |
4 | 30200022013220221 |
5 | 204443123104023 |
6 | 10100032010041 |
7 | 653445506542 |
oct | 144012075051 |
9 | 37576373727 |
10 | 13424425513 |
11 | 5769813644 |
12 | 2727990921 |
13 | 135c2b5b65 |
14 | 914c8b4c9 |
15 | 53883c85d |
hex | 320287a29 |
13424425513 has 4 divisors (see below), whose sum is σ = 14214097620. Its totient is φ = 12634753408.
The previous prime is 13424425501. The next prime is 13424425519. The reversal of 13424425513 is 31552442431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6586458649 + 6837966864 = 81157^2 + 82692^2 .
It is a cyclic number.
It is not a de Polignac number, because 13424425513 - 25 = 13424425481 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13424425519) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 394836028 + ... + 394836061.
It is an arithmetic number, because the mean of its divisors is an integer number (3553524405).
Almost surely, 213424425513 is an apocalyptic number.
It is an amenable number.
13424425513 is a deficient number, since it is larger than the sum of its proper divisors (789672107).
13424425513 is an equidigital number, since it uses as much as digits as its factorization.
13424425513 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 789672106.
The product of its digits is 57600, while the sum is 34.
Adding to 13424425513 its reverse (31552442431), we get a palindrome (44976867944).
The spelling of 13424425513 in words is "thirteen billion, four hundred twenty-four million, four hundred twenty-five thousand, five hundred thirteen".
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