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134244400000 = 27551093079
BaseRepresentation
bin111110100000110010…
…1101111101110000000
3110211111201112002211211
41331001211233232000
54144413031300000
6141400535215504
712461462400244
oct1750145575600
9424451462754
10134244400000
1151a29511727
1222026217594
13c875327a19
1466d707c424
15375a7b37ba
hex1f4196fb80

134244400000 has 192 divisors, whose sum is σ = 337454964000. Its totient is φ = 53187840000.

The previous prime is 134244399899. The next prime is 134244400033. The reversal of 134244400000 is 4442431.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 43598461 + ... + 43601539.

Almost surely, 2134244400000 is an apocalyptic number.

134244400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134244400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168727482000).

134244400000 is an abundant number, since it is smaller than the sum of its proper divisors (203210564000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134244400000 is an frugal number, since it uses more digits than its factorization.

134244400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3227 (or 3195 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 22.

Adding to 134244400000 its reverse (4442431), we get a palindrome (134248842431).

The spelling of 134244400000 in words is "one hundred thirty-four billion, two hundred forty-four million, four hundred thousand".