13424503012142 has 4 divisors (see below), whose sum is σ = 20136754518216. Its totient is φ = 6712251506070.

The previous prime is 13424503012099. The next prime is 13424503012163. The reversal of 13424503012142 is 24121030542431.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13424503012142² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13424503012099 and 13424503012108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3356125753034 + ... + 3356125753037.

It is an arithmetic number, because the mean of its divisors is an integer number (5034188629554).

Almost surely, 2^{13424503012142} is an apocalyptic number.

13424503012142 is a deficient number, since it is larger than the sum of its proper divisors (6712251506074).

13424503012142 is an equidigital number, since it uses as much as digits as its factorization.

13424503012142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6712251506073.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 13424503012142 its reverse (24121030542431), we get a palindrome (37545533554573).

The spelling of 13424503012142 in words is "thirteen trillion, four hundred twenty-four billion, five hundred three million, twelve thousand, one hundred forty-two".