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1342461036557 is a prime number
BaseRepresentation
bin10011100010010000111…
…010011100100000001101
311202100010102021121012202
4103202100322130200031
5133443330011132212
62504415035011245
7165663302351024
oct23422072344015
94670112247182
101342461036557
11478375291443
12198217599b25
1399793cb6344
1448d929438bb
1524dc19dd0c2
hex13890e9c80d

1342461036557 has 2 divisors, whose sum is σ = 1342461036558. Its totient is φ = 1342461036556.

The previous prime is 1342461036547. The next prime is 1342461036577. The reversal of 1342461036557 is 7556301642431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1218575339881 + 123885696676 = 1103891^2 + 351974^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342461036557 - 236 = 1273741559821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1342461036547) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 671230518278 + 671230518279.

It is an arithmetic number, because the mean of its divisors is an integer number (671230518279).

Almost surely, 21342461036557 is an apocalyptic number.

It is an amenable number.

1342461036557 is a deficient number, since it is larger than the sum of its proper divisors (1).

1342461036557 is an equidigital number, since it uses as much as digits as its factorization.

1342461036557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1814400, while the sum is 47.

Adding to 1342461036557 its reverse (7556301642431), we get a palindrome (8898762678988).

The spelling of 1342461036557 in words is "one trillion, three hundred forty-two billion, four hundred sixty-one million, thirty-six thousand, five hundred fifty-seven".