Base | Representation |
---|---|
bin | 111110100001000000… |
… | …0101010001110101011 |
3 | 110211112012210120001001 |
4 | 1331002000222032223 |
5 | 4144421333033103 |
6 | 141401350335431 |
7 | 12461606354032 |
oct | 1750200521653 |
9 | 424465716031 |
10 | 134251455403 |
11 | 51a324a053a |
12 | 2202865a577 |
13 | c876928210 |
14 | 66d7d97719 |
15 | 375b20901d |
hex | 1f4202a3ab |
134251455403 has 4 divisors (see below), whose sum is σ = 144578490448. Its totient is φ = 123924420360.
The previous prime is 134251455397. The next prime is 134251455427. The reversal of 134251455403 is 304554152431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 134251455403 - 29 = 134251454891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134251455473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5163517503 + ... + 5163517528.
It is an arithmetic number, because the mean of its divisors is an integer number (36144622612).
Almost surely, 2134251455403 is an apocalyptic number.
134251455403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
134251455403 is a deficient number, since it is larger than the sum of its proper divisors (10327035045).
134251455403 is a wasteful number, since it uses less digits than its factorization.
134251455403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10327035044.
The product of its (nonzero) digits is 144000, while the sum is 37.
The spelling of 134251455403 in words is "one hundred thirty-four billion, two hundred fifty-one million, four hundred fifty-five thousand, four hundred three".
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