Base | Representation |
---|---|
bin | 11110100001101000011010… |
… | …100011111001001011011111 |
3 | 122121100102020212202121212202 |
4 | 132201220122203321023133 |
5 | 120044043142014331411 |
6 | 1153310432402122115 |
7 | 40164265633624634 |
oct | 3641503243711337 |
9 | 577312225677782 |
10 | 134252533355231 |
11 | 398601a8139355 |
12 | 1308305995033b |
13 | 59bac6224a165 |
14 | 2521c0056418b |
15 | 107c33a98683b |
hex | 7a1a1a8f92df |
134252533355231 has 2 divisors, whose sum is σ = 134252533355232. Its totient is φ = 134252533355230.
The previous prime is 134252533355221. The next prime is 134252533355233. The reversal of 134252533355231 is 132553335252431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134252533355231 - 222 = 134252529160927 is a prime.
It is a super-2 number, since 2×1342525333552312 (a number of 29 digits) contains 22 as substring.
Together with 134252533355233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134252533355233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67126266677615 + 67126266677616.
It is an arithmetic number, because the mean of its divisors is an integer number (67126266677616).
Almost surely, 2134252533355231 is an apocalyptic number.
134252533355231 is a deficient number, since it is larger than the sum of its proper divisors (1).
134252533355231 is an equidigital number, since it uses as much as digits as its factorization.
134252533355231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860000, while the sum is 47.
The spelling of 134252533355231 in words is "one hundred thirty-four trillion, two hundred fifty-two billion, five hundred thirty-three million, three hundred fifty-five thousand, two hundred thirty-one".
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