Search a number
-
+
13425414397 is a prime number
BaseRepresentation
bin11001000000011011…
…11001000011111101
31021122122021201022021
430200031321003331
5204443401230042
610100105120141
7653460065563
oct144015710375
937578251267
1013425414397
11576a3295aa
122728189051
13135c570cb5
14915067a33
15538985867
hex3203790fd

13425414397 has 2 divisors, whose sum is σ = 13425414398. Its totient is φ = 13425414396.

The previous prime is 13425414391. The next prime is 13425414407. The reversal of 13425414397 is 79341452431.

13425414397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10045852441 + 3379561956 = 100229^2 + 58134^2 .

It is an emirp because it is prime and its reverse (79341452431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13425414397 - 227 = 13291196669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425414391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712707198 + 6712707199.

It is an arithmetic number, because the mean of its divisors is an integer number (6712707199).

Almost surely, 213425414397 is an apocalyptic number.

It is an amenable number.

13425414397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425414397 is an equidigital number, since it uses as much as digits as its factorization.

13425414397 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 362880, while the sum is 43.

The spelling of 13425414397 in words is "thirteen billion, four hundred twenty-five million, four hundred fourteen thousand, three hundred ninety-seven".