Base | Representation |
---|---|
bin | 1100001101011101100110… |
… | …1001000001101001111011 |
3 | 1202112110100220012121120021 |
4 | 3003113121221001221323 |
5 | 3224430232044214210 |
6 | 44315315453511311 |
7 | 2553645345622300 |
oct | 303273151015173 |
9 | 52473326177507 |
10 | 13425424210555 |
11 | 4306765a6a855 |
12 | 1609b2b4a2537 |
13 | 76502069a316 |
14 | 345b18a390a7 |
15 | 18435d0e9bda |
hex | c35d9a41a7b |
13425424210555 has 24 divisors (see below), whose sum is σ = 19843196030208. Its totient is φ = 8664475454208.
The previous prime is 13425424210547. The next prime is 13425424210577. The reversal of 13425424210555 is 55501242452431.
It is not a de Polignac number, because 13425424210555 - 23 = 13425424210547 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1611691419 + ... + 1611699748.
It is an arithmetic number, because the mean of its divisors is an integer number (826799834592).
Almost surely, 213425424210555 is an apocalyptic number.
13425424210555 is a deficient number, since it is larger than the sum of its proper divisors (6417771819653).
13425424210555 is a wasteful number, since it uses less digits than its factorization.
13425424210555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3223391203 (or 3223391196 counting only the distinct ones).
The product of its (nonzero) digits is 960000, while the sum is 43.
Adding to 13425424210555 its reverse (55501242452431), we get a palindrome (68926666662986).
The spelling of 13425424210555 in words is "thirteen trillion, four hundred twenty-five billion, four hundred twenty-four million, two hundred ten thousand, five hundred fifty-five".
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