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13425488189 is a prime number
BaseRepresentation
bin11001000000011100…
…01011000100111101
31021122122102110112022
430200032023010331
5204443411110224
610100110445525
7653460523661
oct144016130475
937578373468
1013425488189
11576a379a93
1227282038a5
13135c598769
149150868a1
1553899c65e
hex32038b13d

13425488189 has 2 divisors, whose sum is σ = 13425488190. Its totient is φ = 13425488188.

The previous prime is 13425488137. The next prime is 13425488191. The reversal of 13425488189 is 98188452431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10346348089 + 3079140100 = 101717^2 + 55490^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13425488189 is a prime.

It is a super-2 number, since 2×134254881892 (a number of 21 digits) contains 22 as substring.

Together with 13425488191, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13425488189.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13425488129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6712744094 + 6712744095.

It is an arithmetic number, because the mean of its divisors is an integer number (6712744095).

Almost surely, 213425488189 is an apocalyptic number.

It is an amenable number.

13425488189 is a deficient number, since it is larger than the sum of its proper divisors (1).

13425488189 is an equidigital number, since it uses as much as digits as its factorization.

13425488189 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2211840, while the sum is 53.

The spelling of 13425488189 in words is "thirteen billion, four hundred twenty-five million, four hundred eighty-eight thousand, one hundred eighty-nine".