1342631403445 has 4 divisors (see below), whose sum is σ = 1611157684140. Its totient is φ = 1074105122752.

The previous prime is 1342631403439. The next prime is 1342631403479. The reversal of 1342631403445 is 5443041362431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 858317014116 + 484314389329 = 926454^2 + 695927^2 .

It is a cyclic number.

It is not a de Polignac number, because 1342631403445 - 2²⁷ = 1342497185717 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1342631403398 and 1342631403407.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134263140340 + ... + 134263140349.

It is an arithmetic number, because the mean of its divisors is an integer number (402789421035).

Almost surely, 2^{1342631403445} is an apocalyptic number.

It is an amenable number.

1342631403445 is a deficient number, since it is larger than the sum of its proper divisors (268526280695).

1342631403445 is an equidigital number, since it uses as much as digits as its factorization.

1342631403445 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268526280694.

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 1342631403445 its reverse (5443041362431), we get a palindrome (6785672765876).

The spelling of 1342631403445 in words is "one trillion, three hundred forty-two billion, six hundred thirty-one million, four hundred three thousand, four hundred forty-five".