Base | Representation |
---|---|
bin | 11110100001110100000101… |
… | …100001010011010101110110 |
3 | 122121101121121020202011100011 |
4 | 132201310011201103111312 |
5 | 120044244323201200220 |
6 | 1153320304112210434 |
7 | 40165221324212452 |
oct | 3641640541232566 |
9 | 577347536664304 |
10 | 134265065256310 |
11 | 3986554906609a |
12 | 13085576839a1a |
13 | 59bc1ab656141 |
14 | 252266ca7d662 |
15 | 107c820c7265a |
hex | 7a1d05853576 |
134265065256310 has 16 divisors (see below), whose sum is σ = 242013246984000. Its totient is φ = 53631330653056.
The previous prime is 134265065256293. The next prime is 134265065256313. The reversal of 134265065256310 is 13652560562431.
It is a super-2 number, since 2×1342650652563102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134265065256313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9336923635 + ... + 9336938014.
It is an arithmetic number, because the mean of its divisors is an integer number (15125827936500).
Almost surely, 2134265065256310 is an apocalyptic number.
134265065256310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
134265065256310 is a deficient number, since it is larger than the sum of its proper divisors (107748181727690).
134265065256310 is a wasteful number, since it uses less digits than its factorization.
134265065256310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18673862375.
The product of its (nonzero) digits is 3888000, while the sum is 49.
The spelling of 134265065256310 in words is "one hundred thirty-four trillion, two hundred sixty-five billion, sixty-five million, two hundred fifty-six thousand, three hundred ten".
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